RT @0xacb: How to turn iframes and into weapons for XSS. From origin manipulation to sandbox escape, this paper by….

RT @battledashdev: Just published a new write-up - Hacking 700 Million Electronic Arts Accounts

Generate videos in just a few seconds. Try Grok Imagine, free for a limited time.

IMO a better looking "Search"

RT @noperator: source code for AIxCC cyber reasoning systems:

Even it's hard, I'm still exctied to see small wins like "status code in repeater history"

RT @infosec_au: Today, we're releasing the new Searchlight Cyber (@SLCyberSec) tools website, which allows you to use several of our open-s….

No, this is so much harder than I thought. The technical details of a proxy app is so much more than I'm capable of handling.

We are at a time that building a Burp Suite/Postman from scratch only takes a few days of careful prompting

Current state of Burp AI

RT @jackhcable: AI revolutionized coding. Security hasn't kept up–until now. Introducing @CorridorSecure: the future of secure coding. We….

RT @galnagli: I hacked a popular vibe coding platform with a simple, straight-forward logic flaw - allowing access to private applications….

When people hear I studied Physics, they look at me like I’m some kind of genius. No my friend. I chose Physics because in Hong Kong it had some of the lowest entry requirements 😭😭.

The hookup in the F1 movie was so unnecessary.

RT @Fatnass1F1ras: I just published Cross-Tenant Information Disclosure: Unraveling Microsoft Connections, Custom Connectors, and OAuth… ht….

is this the future of hacking?

RT @siunam321: Here's my research about Python dirty Arbitrary File Write to RCE via overwriting shared object files or overwriting bytecod….

My thought process (didn't get the right answer though). This feels like conditional probabily, but reverse. First, let's calculate the probabily of having 2 heads for a normal coin is 1/2 * 1/2 = 1/4 the probabilty of having 2 heads for a biased coin is 3/4 * 3/4 = 9/16.

You’re given two coins:. One is a fair coin (50/50 heads/tails). The other is biased: it lands heads with probability 75%. You pick one at random, and flip it twice. Both times, it comes up heads. What is the probability you picked the biased coin?.

The pattern is easy now. The probabilty of n dice of above case should be .1: (1/6)^n.2: (2/6)^n - (1/6)^n.3: (3/6)^n - (2/6)^n.4: (4/6)^n - (3/6)^n.5: (5/6)^n - (4/6)^n.6: (6/6)^n - (5/6)^n. average would be the sum of these probabily times the respective result.

Let's start from 3. If I can figure out the patterm jumping from 2 to 3, then i could go from 3 to n. For 3 dice, the intuition is that i should have a higher average than just 2 dice. Let's do this one more time. For the result to be 1, the probabily is for all dice to have.