problem: https://t.co/glboL9IpE4 solution:

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🔢 LeetCode: Number of Substrings with Only 1s ✅ Two approaches: Formula vs incremental! Approach 2 = just add current streak count. Math elegance! ⚡ O(n) single pass 🎯 n×(n+1)/2 vs incremental 💡 5 lines in Approach 2! #LeetCode #CPlusPlus #Math #100DaysOfCode

problem: https://t.co/LD58BLUH9L solution:

🔢 LeetCode: Count Dominant Ones Substrings ✅ Prefix sum + math optimization! Skip impossible ranges, batch count valid ones. O(n × √n) optimization. ⚡ Smart skipping logic 🎯 ones ≥ zeros² constraint 💡 Batch counting FTW #LeetCode #CPlusPlus #PrefixSum #100DaysOfCode

problem: https://t.co/sveWlDq9gN solution:

📊 LeetCode: Increment Submatrices ✅ Difference array magic! Mark boundaries (+1, -1), then prefix sum. Optimize from O(q×n²) to O(q×n + n²). ⚡ Boundary marking technique 🎯 Prefix sum reconstruction 💡 Classic range update trick #LeetCode #CPlusPlus #DifferenceArray

problem: https://t.co/FAMu7QusKv solution: https://t.co/xHrn20Grtt

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⚡ LeetCode: Max Ops Move Ones to End ✅ Elegant greedy! Count 1s, add to result at 1→0 transitions. Each 1 jumps all future 0s. ⚡ O(n) single pass 🎯 Transition detection 💡 Just 7 lines! #LeetCode #CPlusPlus #Greedy #100DaysOfCode

problem: https://t.co/ZkppafJqhk solution:

🔢 LeetCode: Min Ops Make All Elements 1 ✅ GCD magic! Find shortest subarray with GCD=1, reduce it to 1, then propagate. Math > brute force. ⚡ O(n²) with GCD 🎯 ops = (subarray_len-1) + (n-1) 💡 If no GCD=1 subarray → impossible #LeetCode #CPlusPlus #Math #100DaysOfCode

problem: https://t.co/QrWwy1mSe8 solution:

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💰 LeetCode: Ones and Zeroes ✅ 0/1 knapsack with 2 constraints! 3D memo → 2D optimized. Backward iteration = key trick. ⚡ O(len×m×n) time 🎯 2-constraint knapsack 💡 Space: 3D → 2D optimization #LeetCode #CPlusPlus #DynamicProgramming #100DaysOfCode

problem: https://t.co/6rd2pD0ITS solution:

🎯 LeetCode Daily: Min Ops to Zero ✅ Greedy + monotonic stack pattern. Track operation "layers", pop when complete, add when needed. ⚡ O(n) single pass 🎯 Stack tracks active ops #LeetCode #CPlusPlus #Greedy #100DaysOfCode

problem: https://t.co/00Ho3MvZkx solution:

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🎯 LeetCode Daily: Count Operations to Zero ✅ Two approaches: Simulation vs Euclidean! Division replaces repeated subtraction = O(log n) optimization. ⚡ O(n) → O(log n) 🎯 Euclidean GCD pattern #LeetCode #CPlusPlus #40DayStreak #100DaysOfCode