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MathsGenii

@MathsGenii

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An e-learning website for learning mathematics for children aged 7 to 15 years. We provide complete curriculum coverage from Grade 1 to 10.

Bhubaneswar, India
Joined January 2021
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@MathsGenii
MathsGenii
7 months
🌟 Launching my new course on Mathematics Applications and Interpretation HL for IB Diploma 🌟.πŸ‘©β€πŸŽ“πŸ§‘β€πŸŽ“ Enroll today and let’s grow together: #LearnWithMathsGenii #NewCourseAlert
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@MathsGenii
MathsGenii
11 months
🌟 Launching my new course on MCAT Chem Focus: Organic Chemistry 🌟.πŸ‘©β€πŸŽ“πŸ§‘β€πŸŽ“ Enroll today and let’s grow together: #LearnWithMathsGenii #NewCourseAlert
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MathsGenii
1 year
Launching our MCAT (Medical College Admission Test)Β  courses, for students who wants to build career in Medical by joining medical colleges in USA, Canada, Australia and the Caribbean Islands. #MCAT.
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MathsGenii
3 years
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MathsGenii
4 years
What's the answer? Please tell us in the comments.⁠. Answer: D) 0. Explanation:. P(E) = favorable outcomes /total outcomes. Here favorable outcomes are '0'. So probability is '0'. #cbse #maths #ncert #cbsemaths #mathstudent #mathskills #mathstudents #mathslover #mathsclass
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MathsGenii
4 years
What's the answer? Please tell us in the comments.⁠. Answer: B) 2/3. Explanation:. S ={(1,5),(1,6),(1,7),(2,5),(2,6),(2,7),(3,5),(3,6),(3,7),(4,5),(4,6),(4,7)}. n(S) = 12. E ={(1,6),(2,5),(2,6),(2,7),(3,6),(4,5),(4,6),(4,7)}. n(E) = 8. P(E)=n(E)n(S)=8/12 = 2/3. #maths
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MathsGenii
4 years
What's the answer? Please tell us in the comments.⁠. Answer: C) 0.7. Explanation:. P(atleast B) = P( B or A) = P(B) + P(A) = (0.3) + (0.4) = 0.7. #cbse #maths #ncert #cbsemaths #mathstudent #mathskills #mathstudents #mathslover #mathsclass #mathspuzzle #mathsexam #mathsquestions
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MathsGenii
4 years
What's the answer? Please tell us in the comments.⁠. Answer: B) 103/108. Explanation:. Total number of events=6 x 6 x 6=216. So,B={(1,1,1),(1,1,2),(1,2,1),(2,1,1),(1,1,3),(1,3,1),(3,1,1),(1,2,2),(2,1,2),(2,2,1)}. =10. P(B)=10/216. => P(A) = 1 - P(B). = 1 - (10/216) = 103/108
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MathsGenii
4 years
Enjoy your freedom, but also respect the numerous sacrifices made by our leaders. Happy Republic Day!. #mathsgenii
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MathsGenii
4 years
What's the answer? Please tell us in the comments.⁠. Answer: B) p/(p+q). Explanation:. Total number of cases=p+q. Favourable cases=p. Probability of that event is=p/(p+q). #cbse #maths #ncert #cbsemaths #mathstudent #mathskills #mathstudents #mathslover #mathsclass #mathspuzzle
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MathsGenii
4 years
What's the answer? Please tell us in the comments.⁠. Answer: C) 1/3. Explanation:. Total number = 6. Getting a 'multiple of 3' = 2. So, probability = 2/6 =1/3.⁠.#cbse #maths #ncert #cbsemaths #mathstudent #mathskills #mathstudents #mathslover #mathsclass #mathspuzzle #mathsexam
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MathsGenii
4 years
What's the answer? Please tell us in the comments.⁠. Answer:Β A) 3/91. Explanation:. n(S) = (15 – 1)! = 14 !. = (13 - 1)! = 12!. = n(E) = 12! X 3!. = n(E) / n(S) = 12! X 3 ! / 14!. = 12!x3x2 / 14x13x12! = 6/14x13 = 3/91. #cbseΒ #mathsΒ #ncertΒ #cbsemathsΒ #mathstudent
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MathsGenii
4 years
What's the answer? Please tell us in the comments.⁠.⁠.Answer : A) Two.⁠.Explanation:⁠. FA - IN - TS.AF - IN - ST.⁠.When the letters are arranged in the alphabetical order, two remains the same. ⁠.#cbse #maths #ncert #cbsemaths #mathstudent
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MathsGenii
4 years
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@MathsGenii
MathsGenii
4 years
What's your answer? Please tell us in the comments. Answer: C) 21/38. Explanation:. n(S) = 20c2 = 190. n(E)= 15c2 = 105 . Therefore, P(E) = 105/190 = 21/38
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@MathsGenii
MathsGenii
4 years
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